IUPAC name of the following
O2N-CH=CH-COOH
Answers
For a: The name is But-2-en-oic acid.
For b: The name is pentane.
For c: The name is propanol.
Explanation:
IUPAC naming for the given hydrocarbons is given by following some rules.
For a:
The functional group present in this compound is carboxylic acid and double bond. The rules for the naming of carboxylic acid is given as:
1. Out of double bond and carboxylic acid, functional group is given the priority.
2. The longest continuous carbon chain must contain the carboxylic group which gets the lowest number.
3. The naming of carboxylic acids is done by adding the suffix -oic acid of the corresponding chain.
4. The prefix for the number of carbon atoms in the chain are given as follows: Meth for 1, Eth for 2, Prop for 3, But for 4, Pent for 5, Hex for 6, Sept for 7, Oct for 8, Nona for 9 and Dec for 10.
Thus, the IUPAC name given to the chain is but-2-en-oic acid.
For b:
There is no functional group in this compound. The rules for writing the name for this chain is:
1. In the nomenclature of alkane, a suffix is added which is -ane to the stem name.
2. Stem name indicates the number of carbon atoms in a chain which are described as Meth for 1, Eth for 2, Prop for 3, But for 4, Pent for 5, Hex for 6, Sept for 7, Oct for 8, Nona for 9 and Dec for 10.
Thus, the IUPAC name given to the chain is pentane.
For c:
The functional group present in this compound is alcohol. The rules for the naming of alcohol is given as:
1. The selected longest continuous chain of carbon atom must contain hydroxy group.
2. The alcohols are named by suffixing -ol to the stem chain.
3. The carbon having hydroxyl group gets the highest priority and lowest possible numbering.
4. If a compound contain two or more hydroxyl groups then the suffixes used as, -diol, triol, and so on.
5. The unsaturated alcohols are named by replacing -ane by suffix -enol or -ynol of the corresponding chains.
Thus, the IUPAC name given to the compound is propanol.
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