Math, asked by prativabehera012, 10 months ago

IUUU
(a) Rs 278.6U (6) Rs 350
(c) Rs 432
30. A man sells an article at a loss of 10%. Had he bought it at 20% less and
sold it for Rs 55 more, he could have gained 40%. What is the cost price of
the article ?
c) None of these​

Answers

Answered by JessicaRoyale1
0

Answer:

Please proceed downwards!

Step-by-step explanation:

Let S.P. symbolize the Selling Price and C.P. symbolize Cost Price

Let's try expressing S.P. in terms of C.P. :

S.P. = (100 - L%)/ 100 * C.P.

      = (100-10)/100 * C.P.

      = 90/100 C.P. (Rs)

New C.P. = 20/100 C.P. (Rs)

New S.P. = 90/100 C.P. + 55 Rs = 9/10 * C.P. + 55 Rs

But, New S.P. =  (100 + G%)/100 * C.P.

                       =   (100 + 40)/100 * C.P.

                       = 140/100 * C.P. = 14/10 * C.P.

So,

9/10 * C.P. + 55 = 14/10 * C.P.

55 = 14/10 * C.P. - 9/10 * C.P.

55 = 5/10 * C.P.

(55 * 10)/5 = C.P.

110 = C.P.

So, the C.P. is 110 Rs.

Edit: Nahhhhhh! THIS IS WRONG.....Here is the correct answer:

Let ‘x’ be the cost price of the article.

Then selling price = x * 110/100 = 1.1x

If he had bought for 20% less, then cost price = 0.8x

With 40% profit, selling price will be = 0.8x * 140/100 = 1.12x

Hence we have, 1.12x - 1.10x = 10

0.02x = 10

x = 10/.02 = ₹500

Credits to:  

Ramesh Mathrubootheswaran at Quora

Quora

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