Question

(iv) (0.1p+ 0.2q) (0.29 - 0.1p); p = 10,q = 5​

Answer 1

Answer:

Given,

0.2p + 0.3y = 1.3.(1) and

0.4p + 0.5q = 2.3.(2).

Now, (2) -2 x (1) gives,

-0.1q = -0.3

or, q = 3.

Using value of q in (1) we get,

p=2.