Question

(iv)1/15,1/12,1/10,...,to 11 term​

Answer 1

Answer:

Given:

1/15,1/12,1/10..........to 11 terms

a=1/15

d=1/12-1/15

 =1/60

Sn= n/2[2a+(n-1)d]

S11= 11/2[2 x1/15+(11-1)x 1/60]

    = 11/2[2/15 +10 x 1/60]

    = 11/2[ 2/15+10/60]

    = 11/2[18/60]

    = 11/2 x 18/60

S11= 33/20

                    I hope this answer will be helpful to you.