Math, asked by mhussainrizvi93, 7 months ago

(iv) 2 y3+ y2 - 2y-1 factories​

Answers

Answered by anindyaadhikari13
3

\star\:\:\:\bf\large\underline\blue{Question:-}

  • Factorise the polynomial.

\star\:\:\:\bf\large\underline\blue{Solution:-}

2 {y}^{3}  +  {y}^{2}  - 2y - 1

 =  {y}^{2} (2y - 1) - 1(2y - 1)

 = ( {y}^{2}  - 1)(2y - 1)

 = ( {y }^{2}  -  {1}^{2} )(2y - 1)

 = (y + 1)(y - 1)(2y - 1)

\star\:\:\:\bf\large\underline\blue{Answer:-}

  •  (y + 1)(y - 1)(2y - 1)
Answered by tennetiraj86
3

Answer:

answer for the given problem is given

Attachments:
Similar questions