Question

(iv) 27000
1. Find the cube root of each of the following numbers by prime factorisation method
(i) 64
(ii) 512
(iii) 10648
(v) 15625 (vi) 13824 (vii) 110592
(viii) 46656
(ix) 175616
(x) 91125​

Answer 1

l.C.M 64

$\sqrt[3]{64} = 2 \times 2 \times 2 \times 2 \times 2 \times 2$

$\sqrt[3]{?64} = 2 \times 2 = 4$

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(ii) 512

L.C.M 512

$\sqrt[3]{512} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2$

$\sqrt[3]{512} = 2 \times 2 \times 2 = 8$

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(iii) 10647

l.c.m 10648

$\sqrt[3]{10648} = 2 \times2 \times 2 \times 11 \times 11 \times 11$

$\sqrt[3]{10648} = 2 \times 11 = 22$

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(iv) 27000

l.C.M 27000

$\sqrt[3]{27000} = 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 5 \times 5 \times 5$

$\sqrt[3]{27000} = 2 \times 3 \times 5 = 30$

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(v) 15625

l.C.M 15625

$\sqrt[3]{15625} = 5 \times 5 \times 5 \times 5 \times 5 \times 5$

$\sqrt[3]{15625} = 5 \times 5 = 25$