Question

iv) 2log(x + 1) = log 2 + log x​

Answer 1

Answer:

log(x+1)^2=log2+logx

log(x^2+1^2+2x)=log2+logx

logx^2*log1^2*log2x=log2+logx

logx^2*log1^2*log2x=log2+logx

logx^2*log1^2*log2+logx=log2+logx

logx^2*log1^2=1

2logx*2log1=1

2(logx*o)=1

logx=1/2

x=e^1/2