Question

(iv) 2p + 3q +4r + pqr when p=1,q = 2and r = 3​

Answer 1

Answer:

And the answer is 26

Step-by-step explanation:

If p=1

Therefore 2p = 2*1=2 ------------------- 1

And if q=2

then 3q = 3*2=6--------------------2

And if r=3

then 4r = 4*3=12-------------------3

and

p*q*r =1*2*3=6--------------------4

According to the given question

2p+3q+4r+pqr =2+6+12+6=26-------------( From 1 and 2 and 3 and 4)

Answer 2

Answer: 26

Step-by-step explanation:

Given equation is 2p + 3q + 4r + pqr

When, p=1, q=2 and r=3​

Then,2p + 3q + 4r + pqr = 2×1 + 3×2 + 4×3 + 1×2×3

= 2+6+12+6

=26