(iv) 2y^3+ y2 - 2y-1
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Answer:
(y^2 - 1) (2y + 1)
Step-by-step explanation:
2y^3 + y^2 - 2y - 1
=2y^3 - 2y + y^2 - 1
=(2y^3 - 2y) + ( y^2 - 1)
=2y(y^2 - 1) + 1( y^2 - 1)
=(y^2 - 1) (2y + 1)
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