Math, asked by ykuldeep868, 10 months ago

(iv) 2y^3+ y2 - 2y-1​

Answers

Answered by peter12tyo
3

Answer:

(y^2 - 1) (2y + 1)​

Step-by-step explanation:

2y^3 + y^2 - 2y - 1​

=2y^3 - 2y +  y^2 - 1​

=(2y^3 - 2y) + ( y^2 - 1)​

=2y(y^2 - 1) + 1( y^2 - 1)​

=(y^2 - 1) (2y + 1)​

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