Question

(iv) 2y³ + y² – 2y-1 Factorise plz​

Answer 1

Answer:

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2y ^{3} + y ^{2} - 2y - 1 \\ \\ = y ^{2}(2y + 1) -1 (2y + 1) \\ \\ = (2y + 1)(y ^{2} - 1) \\ \\ = (2y + 1)(y + 1)(y - 1)

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Answer 2

Answer:

$= 2 {y}^{3} + {y}^{2} - 2y - 1 \\ = 2 {y}^{3} - 2y+ {y}^{2} - 1 \\ = 2y( {y}^{2} - 1) + 1( {y}^{2} - 1) \\ = (2y + 1)( {y}^{2} - 1) \\ = (2y + 1)(y + 1)(y -1 )$

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