(iv)
4
(e) Factors of 2x3 + 5x – 6x2 – 15 are-
(i) (2x + 5) and (x + 3)
(iii) (2x2 + 5) and (x – 3)
(ii) (2x2 – 5) and (x + 3)
(iv) (2x – 5) and (x + 3)
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Answer:
answer is (2x-5) and ( x+3)
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