Question

(iv) (6x5 – 28x3 + 3x2 + 30x – 9) by (2x2 – 6)​

Answer 1

Answer:

Hey mates your answer is here

3x^3 - 5x + 3/2

To solve (6x^5 – 28x^3 + 3x^2 + 30x - 9) / (2x^2 - 6)...

Factor the top and bottom so that you can cancel things out afterward. Starting with the top.

6x^5 – 28x^3 + 3x^2 + 30x - 9

You'll want to break up -28x^3 by finding two numbers that multiply to get 180 (6 * 30 from 6x^5 and 30x) and add to get -28 from -28x^3. These numbers are -10 and -18.

May be it's helpful for you

Please mark me as a brainlest

6x^5 - 10x^3 - 18x^3 + 3x^2 + 30x - 9

6x^5 - 10x^3 - 18x^3 + 30x + 3x^2 - 9

x^2(6x^3 - 10x) - 3(6x^3 - 10x) + 3(x^2 - 3)

(x^2 - 3)(6x^3 - 10x) + 3(x^2 - 3)

(x^2 - 3)(6x^3 - 10x + 3)

Now for the bottom...

2x^2 - 6

2(x^2 - 3)

Now you have...

(x^2 - 3)(6x^3 - 10x + 3) / 2(x^2 - 3)

You can cancel out (x^2 - 3) from the top and bottom.

(6x^3 - 10x + 3) / 2

Divide everything in the top by 2 to remove the bottom.

(6/2)x^3 - (10/2)x + 3/2

3x^3 - 5x + 3/2

This is the simplest form.