Question

(iv) 76 x 88 - 76 x 90 – 76 x 2
3. What number should replace each
() 345 + 6) = (3 * 5) + (
36)
(ii) (7 * 4) + (n x 3) = 7(4+3)
(iii) o 8) + (8 x 8) - (9+8) n
4. Multiply by suitable arrangement:
(i) 20,5,8,7 (ii) 25, 4, 598
(iii) 4,2893, 250 (iv) 2,2867,50​

Answer 1

Answer:

iv) 76 * 88 - 76 * 90 -76 *2

take 76 as common

76 ( 88-90-2)

76( -2-2)

76 * -4 = -304

3)sorry couldnt understand this question

ii) (7*4) + (n * 3) = 7(3+4)

28 + 3n = 7(7)

28 + 3n = 49

3n = 49-28

3n = 21

n = 21/3 == n =7

ii) ( 0*8)+(8*8) = (9+8)n

0. + 64 = 17n

n = 64/17

4. multiply making suitable arrangements

1) 20,5,8,7 => (20*5) (8*7) => 100 * 56 => 5600 2)25,4,598 => (25*4) (598)=> 100*598 = 59800 3)4,2893,250=> (250*4) (2893) = 1000*2893= = 2893000

4)2,2867,50 =>( 50*2 ) * 2867 = 100*2867 = =286700

Answer 2

Answer:

Step-by-step explanation:76*88=76*90-76*