Question

(iv) 9z2 – x2 – 4y2 + 4xy
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Answer 1

Answer:

$\Large\boxed{2(9Z-X-4Y+2XY)}$

Step-by-step explanation:

Given:

$\Large\boxed{\textnormal{FIND THE FACTORS}}$

$\Large\boxed{\textnormal{SUBJECT: MATH }}$

To solve this problem, first you have to find the factors of 9z2-x2-4y2+4xy.

Solutions:

First, thing you do is multiply the numbers from left to right.

$\displaystyle 2*9=18$

$\displaystyle 18z-2x-4*2y+4xy$

Next, multiply again.

$\displaystyle 2*4=8$

$\displaystyle 18z-2x-8y+4xy$

You can also find the factors of 9z2-x2-4y2+2xy from left to right numbers.

Rewrite the whole problem down.

$\displaystyle 18z-2x-8y+4xy$

$\displaystyle 2*9z-2x-2*4y+2*2xy$

Solve.

Find the common term of 2.

$2*9z-2x-2*4y+2*2xy=\boxed{2(9Z-X-4Y+2XY)}$

$\Large\boxed{2(9z-x-4y+2xy)}$

In conclusion, the correct answer is 2(9z-x-4y+2xy).

Answer 2

Answer:

(x-2y+3z)(-x+2y+3z)

Step-by-step explanation:

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