(iv) (a - 2, 2b + 1) = (b - 1, a +2)
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Answered by
4
(a-2 ,2b+1)=(b-1 ,a+2)
a+2=b-1. ; 2b+1=a+2
a-b=-3. ; 2b-a=1
a-b=-3 -----(1) ; -a+2b =1--------(2)
Eliminating the given equations.....
We get,
a - b = -3
-- a+2b = 1
_____________
b=-2
Placing the value of b=-2 in eq.(1)
We get,
a -(-2)= -3
a +2 = -3
a = -1
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Answered by
3
Answer:
a=3 , b=2
Step-by-step explanation:
given - (a-2 , 2b+1) = (b-1 , a+2)
a-2 = b-1
a-b = 1 -> equation (1)
2b+1 = a+2
a-2b = -1 -> equation (2)
by multiplying equation (1) by 2, we get : 2a - 2b = 2 -> equation (3)
by sutracting equation (2) from equation (3),
2a - 2b = 2
-a +2b = -1
-----------------
a = 3
-----------------
by taking equation (1) and putting value of a in (1),
a - b = 1
3 - b = 1
-b = 1-3
-b = -2
b = 2
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