Question

(iv) a + ab
(vi) 4y2 - 3y
(iv) a + b + 3
(vii) 9x’y - 8xy
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Answer 1

$iv) Given \: a + ab$

$= a(1+b)$

$vi) Given \: 4y^{2} - 3y$

$= y(4y-3)$

$iv) a+b+3$

$= 1(a+b+3)$

$vii ) Given \: 9xy - 8xy$

$= (9-8)xy$

$= xy$

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Answer 2

• A + A B = A (1 + B )= A (1) = A

• Factoring: 4y2-3

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2