iv. A body falling freely will cover a distance of ………during first second of its motion
Answers
Answered by
5
s=ut+1/2at^2
here I am taking u=0ms^-1 ,t=1 secs, a=10ms^-2
so s=0*1+1/2*10*(1)^2=0+5=5m
so the distance covered in first second is 5 metres.
here I am taking u=0ms^-1 ,t=1 secs, a=10ms^-2
so s=0*1+1/2*10*(1)^2=0+5=5m
so the distance covered in first second is 5 metres.
Yatj:
plz mark as brainliest
Similar questions