Question

(iv) A car accelerates uniform from 18km/h to 36km/h in 2 seconds. Calculate
the distance covered by the car in that time.​

Answer 1

Answer:

1.

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Answer 2

Given :

• Initial velocity of Car, u = 18 km/h
• Final velocity of Car, v = 36 km/h
• Time taken for change in velocity, t = 2 s

To find :

• Distance covered by Car in this time, s =?

Formula required :

• First equation of motion

      v = u + a t

• Third equation of motion

     2 a s = v² - u²

[Where,

v = final velocity, u = initial velocity, a = acceleration, t = time taken, s = distance covered]

Solution :

Converting Initial and final velocities given in km/h into m/s

→ u = 18 km/h

→ u = 18 × 5/18  m/s

→ u = 5 m/s

and,

→ v = 36 km/h

→ v = 36 × 5/18  m/s

→ v = 10 m/s

Calculating acceleration of Car

Using first equation of motion

→ v = u + a t

→ 10 = 5 + a × 2

→ 2 a = 10 - 5

→ 2 a = 5

→ a = 5/2

→ a = 2.5 m/s²

Calculating Distance covered by Car in this time

Using third equation of motion

→ 2 a s = v² - u²

→ 2 × 2.5 × s = 10² - 5²

→ 5  s = 100 - 25

→ 5 s = 75

→ s = 75 / 5

→ s = 15 m

Therefore,

• Distance covered by Car in this time is 15 metres.