Question

iv) A coin is tossed three times. What is the probability of getting no tail?
(A)3/8
(B)1/2
(C)3/8
(D)5/8

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Answer 1

Answer:

None of the options are correct. The correct answer is  $\frac{1}{8}$.

Step-by-step explanation:

Assume the coins is fair, that is there's $\frac{1}{2}$ chance to get heads and $\frac{1}{2}$ chance to get tails. Then getting no tails is the same as getting only heads. As each toss is independent then the chance of only getting heads (that is getting no tails) is $\left( \frac{1}{2} \right)^{3} = \frac{1}{2^3} = \frac{1}{8}$.

If you do not find this answer satisfactory then you can also write out all the possible combinations of heads (H) and tails (T):

HHH    HHT    HTH    HTT

TTT    TTH    THT    HHT

As you can see from the above only HHH (only heads) have no tails, which is 1 out of 8 possible combinations, hence  $\frac{1}{8}$.

Answer 2

Answer:

your answer incorrect ismath