Question

iv) A current of 0.5 A flows through a copper wire, when
potential difference of 50V produced, find the power.​

Answer 1

Answer:V=IR

⇒15=(0.2)R

⇒(3)×5×5=R

⇒R=75Ω

By Joule's Law,

P=VI

P−(15)(0.2)

P=3 W

Step-by-step explanation:

Answer 2

Step-by-step explanation:

to find power we need to find Resistance

so,

V=IR

50 = 0.5 *R

R = 100 ohms

P = I²R

= 0.25 * 100

= 25 watt