Question

iv) A rectangular magnet suspended freely
has a period of oscillation equal to T.
(each having half of the original length)
Now it is broken into two equal halves
and one piece is made to oscillate freely.
Its period of oscillation is T', the ratio of
T' / T'is.​

Answer 1

Answer:

1/2

Explanation:

As we know Time period for oscillating magnet is

T=2π* root of I/MB.........(1)

where I is the moment of inertia,

M is the magnetic moment

M=x×l

x=polestrength

When the magnet is broken in two equal parts, the new magnetic dipole moment is

M′=x×l/2=M/2

I′=ML^12\2

=M/2×L^2/2

=ML^2/12*8

=I/8

New time period is

T′=2π* root of I' / M′B

Putting all the values we get

T′/T=root of 1/4= 1/2

So the final answer is 1/2.

Answer 2

Answer:

()

Explanation: