(iv) (a²- b²)(a² +b²) - (a² – b²)^2
Answers
Answered by
1
Answer:
2b² (a + b) (a - b)
Step-by-step explanation:
There is a common divisor .
- ma+mb=m(a+b)
Let's solve the problem.
→(a² - b²) (a² + b²) - (a² - b²)²
=(a² - b²) (a² + b²) - (a² - b²) (a² - b²)
=(a² - b²) { (a² + b²) - (a² - b²) }
=(a² - b²) (a² + b² - a² + b²)
=(a² - b²) × 2b²
- (a + b) (a - b) = a² - b²
→2b² (a + b) (a - b)
Answered by
0
Answer:
Step-by-step explanation:
(a²-b²)(a²+b²)=a⁴-b⁴=(a²)²-(b²)²
a⁴-b⁴-2(a²-b²)+1-1=[ (a²)²-2a²+1]-[(b²)²-2b²+1]
= (a²-1)²-(b²-1)²=(a²-b²-2)(a²+b²)
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