Question

iv. According to given conditions in question (iii), equation of parabola is
.y=X
b. ya
c. y=-x?
d.y=-x-
following is not the pranh of a quadratic polynomial?​

Answer 1

Answer:

Step-by-step explanation:

since y = mx + b is an equation of degree one, the quadratic function, y = ax2 + bx + c Since each point on the basic parabola satisfies the equation y = x2 we can express the . c: Sketch the parabola showing the y-intercept and the x-intercepts.  Use transformations to give a quick sketch the following parabolas. a y