Math, asked by sushilkumar7380, 3 days ago

(iv) ADEF when DE = 12 cm, EF = 8 cm, FD = 14 cm ​

Answers

Answered by shreychaudhary839
0

Answer:As per the dimensions give in the questions,

Now, we have to find out the perimeter of △ABC

Let △ABC∼△DEF

So, AB/DE=AC/DF=BC/EF

Consider, AB/DE=AC/DE

4/6=AC/12

By cross multiplication we get,

AC=(4×12)/6

AC=48/6

AC=8cm

Then, consider AB/DE=BC/EF

4/6=BC/9

BC=(4×9)/6

BC=36/6

BC=6cm

Therefore, the perimeter of △ABC=AB+BC+AC

=4+6+8

=18cm.

Step-by-step explanation:

hope it help you

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