Question

(iv) An elevator descends into a mine shaft at the rate of 8 m/min. If the descent starts from 20 m above ground
level, how long will it take to reach - 460​

Answer 1

Answer:60 minutes or 1 hour

Step-by-step explanation: level above ground = 20m

                                            level below the ground = - 460m

Therefore the total distance= (20-(-460)) m

                                               = (460 + 20) m

                                                  =480 m

Speed = 8m/min.

We know that time = distance/ speed

                                = (480/8) min

                                   =60 min or 1 hour

Answer 2

Answer:

60 min or 1hr . this is my answer