Question

(iv) An object takes 5 s to reach the ground from a height of 5 m on a planet.
What is the value of 'g' on the planet?​

Answer 1

→ In this question we will use kinematics equation.

→ Since we have the height and time we will use the following kinematics equation :

$→ S = ut + \frac{1}{2} gt²$

Where :

• S = height
• u = initial velocity.
• t = time in seconds
• g = gravitational acceleration

→In our case the initial velocity = 0

→ Doing the substitution we have :

$→5 = 0 × 5 + \frac{1}{2} × g × 5²$

$→ 5 = 12.5g$

$→ g = \frac{ 5}{12.5}$

$→ g = 0.4$

• Therefore, The g on the planet is 0.4m/s².

Answer 2

Answer:

0.4m/s¹

Explanation:

here,u=0

s=5m

t=5s

from second equation of motion,we have

s=ut + 1 /2 gt²

5=1/2g(5)²

g=10/25=0.4m/s²

hence,the value of g on the planet is 0.4 m/s¹