Question

iv) Convert the following.
a) 40°C to °F

b) 105°F to °C​

Answer 1

Answer:

Explanation:

(40°C × 9/5) + 32 = 104°F

(105°F − 32) × 5/9 = 40.556°C

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Answer 2

Answer:

a)  $40^0 C= 104^0F$

b)  $105^0F= 40.555^0C$

Explanation:

We have the equations for converting

• The temperature in Celcius scale to temperature in Fahrenheit scale   as,  

        $F=\frac{9}{5} C+32$       ...(1)

        and

• The temperature in Fahrenheit scale to Celcius scale as,

        $C= \frac{(F-32) \times 5}{9}$     ...(2)

Where,

C - the temperature on the Celcius scale and

F  - the temperature on the Fahrenheit scale.  

In question (a), it is given that,

$C = 40^0 C$

Using equation (1),

$F=(\frac{9}{5}\times 40)+32$

    $= 72+32= 104^0F$

From question(b),

$F =105^0F$

Using equation (2),

$C= \frac{(105-32) \times 5}{9}$

     $=40.5555 ^0 C$