Question

(iv) Dimension of permeability is
Mark
(b) MLT?A?
(d) MLTA?
(a) MLTA?
(c) MLTA
चुम्बकशीलता की विमा है :
(a) MLT'A
(c) MLTA
-2
(b) MLT A 2
(d) MLTA?​

Answer 1

Answer:

answer is ( c )

Explanation:

Units of permeability are equivalent to N/(amp)2 thus dimensions are = [M1L1T−2][A2]=[M1L1T−2A−2]