iv) एक मीनार पर ध्वजदंड खड़ा है। मीनार से 10 मीटर दूर जमीन पर मीनार और
ध्वजदंड क्रमशः 45तथा 15 के कोण बनाते हैं। ध्वजदंड की लम्बाई ज्ञात
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Step-by-step explanation:
Height = \begin{gathered}\frac{21 - 7\sqrt{3} }{2} \\\end{gathered}221−73
Step-by-step explanation:
I have attached the question figure drawn by me in this answer.
Let h be the height of the minar and b be the distance between the bases of the house and the minar.
So, \frac{h}{b}bh = tan 60°
b = \frac{h}{\sqrt{3} }3h
Now as shown in the figure,
\frac{x}{b}bx = tan 45°
so x = b
Also, x + h = 7 (Height of house is 7m)
b + h = 7
\frac{h}{\sqrt{3} }3h + h = 7
h(1 + \frac{1}{\sqrt{3} }31 ) = 7
h(\frac{\sqrt{3} + 1 }{\sqrt{3} }33+1 ) = 7
h = \frac{7\sqrt{3} }{\sqrt{3} + 1 }3+173
now rationalising
h = \frac{21 - 7\sqrt{3} }{2}221−73
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