Question

iv) Find the area of a square with side 8 cm.
v) In A PQR, if _ P = 90°, then write the name of the hypotenuse.
vi) What is the average of the numbers 2,3,4,5,6?​

Answer 1

Answer:

iv) Area of square = side ^2

= 8×8 = 64

v) side QR is the hypotenuse.

According to Pythagoras' theorem,

l(QR)2 = l(PQ)2 + l(PR)2

⇒l(QR)2 = (24)2 + (10)2

⇒l(QR)2 = 576 + 100

⇒l(QR)2 = 676

⇒l(QR)2 = (26)2

⇒l(QR) = 26

∴ Length of seg QR = 26 cm.

vi) Average = sum of given number / total number

= 20/5

= 4

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

iv) A=64cm²

v) In given right angle

∠P=90°

QR=12cm

BY using 30°−60°−90° triangle, we get special relationship between its sides.

All of us know in right angle triangle hypotenuse is longest side.

So, longest side=12m

shortest side= 12/6

vi) sum of data=20

Average =sum of date /no of scores

=20/5

=4

hope it helps you dear