Question

iv.
Find the oxidation state of Sulphur in the following compounds:
2. HAS
b. H:SO
c. Nags:03
d. H.SO.
plz only tell answer of them​

Answer 1

Answer:

H2S,H2SO4,S2O42−,S2O82−

In H2S,+2+x=0;x=−2

In H2SO4+2+x−8=0;x=+6

In S2O42−2x−8=−22x=6,x=+3

In S2O42−,Let one of S=x, then 2x+4(−8)=−2∴x=+3

In S2O82− there is peroxide linkage, therefore oxidation state of ′S′ is 6 because