Question

(iv) find the zeros for p(x) is equal to x power4 minus 16​

Answer 1

ok this is your answer

I hope you get your answer

Answer 2

Answer:

+2 and -2

Step-by-step explanation:

$p(x) = {x}^{4} - 16 \\ = > p(x) = 0 \\ {x}^{4} - 16 = 0 \\ {x}^{4} = 16 \\ x = \sqrt[4]{16} \\ x = \pm2$

The zeroes of the polynomial are +2 and -2