Question

(iv) For quadratic equation 10x2 + 10x + 1 = 0, what is the value of the
discriminant ?
plz answer this question girls/boys​

Answer 1

Answer:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

STEP

1

:

Equation at the end of step 1

((0 - (2•5x2)) - 10x) + 1 = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

-10x2 - 10x + 1 = -1 • (10x2 + 10x - 1)

Trying to factor by splitting the middle term

3.2 Factoring 10x2 + 10x - 1

The first term is, 10x2 its coefficient is 10 .

The middle term is, +10x its coefficient is 10 .

The last term, "the constant", is -1

Answer 2

Answer:

60

Step-by-step explanation:

Standard equation of a quadratic equation is :

ax²+bx+c = 0

On comparing , a =10 , b = 10 , c = 1

Discriminant = b²- 4ac

Therefore discriminant = 10²- 4(10)(1)

= 100 - 40 = 60