(iv)
For the quadratic equation (k-1)n2 =kn-1;
k#1, then roots are numerically equal but
opposite sign then k=
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Answered by
0
(k-1)n²=kn-1
(k-1)n²-kn+1=0
Given : -b/a = - c/a
=> b = c
-k = 1
k = -1
Answered by
7
Answer:
(k-1)n^2=kn-1
(k-1)n^2-kn+1=0
Given:-b/a=-c/a
=b=c
-k=1
k=-1
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