Question

iv) If V1 = 2i-3j+k and V2 = i - j –k determine V1+V2 ? ​

Answer 1

Answer:

1.v₁⁻¹ = (2i + 3j - k) / (2² + 3² + (-1²)) = (2i + 3j - k) / 14 = (1/7)i + (3/14)j - (1/14)k

2.(1/14)k

v₂⁻¹ = (i - j - 2k) / (1² + (-1)² + (-2²)) = (i - j - 2k) / 6 = (1/6)i - (1/6)j - (1/3)k

3.

v₃⁻¹ = (i + 2j + 2k) / (1² + 2² + 2²) = (i + 2j + 2k) / 9 = (1/9)i + (2/9)j + (2/9)k

The rule is that we must divide each vector by the sum of the squares of its coordinates. So: