Question

iv)
In the adjoining figure, It is given that CE | BA, ZBAC = 90° and L ECD = 250,
Find () ZACE
(ii) ZACB (iii) LABC
E
900
250​

Answer 1

L ECD = 250,

L ECD = 250,Find () ZACE

L ECD = 250,Find () ZACE(ii) ZACB (iii) LABC

L ECD = 250,Find () ZACE(ii) ZACB (iii) LABCE

L ECD = 250,Find () ZACE(ii) ZACB (iii) LABCE900

L ECD = 250,Find () ZACE(ii) ZACB (iii) LABCE900250

FØŁŁØW MƏ

Answer 2

Answer : In the adjoining figure it is given that CE Parallel line BA angle BAC ... angle ECD=35° find Angle ACE ,angle ACB, angle ABC ... Solue for X:(x + 1)(x+3)-8= 5(x+1( x+2).