Question

iv)
It seca
sec
siñ
1-cOS​

Answer 1

Answer:

Step-by-step explanation:

Given that,

\frac{1 + sec a}{sec a} = \frac{sin 2a}{1 - cos a}

Let, L.H.S

\frac{1 + sec a}{sec a}

\frac{1 + (\frac{1}{cos a})}{\frac{1}{cos a}}]

\frac{\frac{cos a + 1}{cos a}}{\frac{1}{cos a}}

cos a + 1

Multiple and divide with (1 - cos a)

(1 + cos a)\times \frac{1 - cos a}{1 - cos a}

\frac{1 - cos^2 a}{1 - cos a}

\frac{sin 2a}{1 - cos a}

R.H.S

Answer 2

Answer:

Let, L.H.S

\frac{1 + sec a}{sec a}

\frac{1 + (\frac{1}{cos a})}{\frac{1}{cos a}}]

\frac{\frac{cos a + 1}{cos a}}{\frac{1}{cos a}}

cos a + 1

Multiple and divide with (1 - cos a)

(1 + cos a)\times \frac{1 - cos a}{1 - cos a}

\frac{1 - cos^2 a}{1 - cos a}

\frac{sin 2a}{1 - cos a}

R.H.S