Question

IV. NUMERICAL PROBLEMS
1. The actual weight of an object is 98 N. When an obiect is moving downwards through a lift
with an acceleration of 4 m/s, Calculate the apparent weight of the object
2. A car of mass of 1200 kg is moving with a velocity of 30m/s. On applying brakes,its
Velocity is reduced to 10 m/s. Find the change in momentum.
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Answer 1

Answer:pagal hai kya aisa questions pucha jata hai

Explanation:

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Force=20\:N}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt : \implies Initial \: velocity(u) = 2 \: m/s \\ \\ \tt : \implies Final \: velocity(v) = 10 \: m/s \\ \\ \tt : \implies Time(t) = 10 \: sec \\ \\ \tt : \implies Mass(m) = 10 \: kg \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Force \: require(F) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 10 = 2 + a \times 4 \\ \\ \tt: \implies 10 - 2 =a \times 4 \\ \\ \tt: \implies a = \frac{8}{4} \\ \\ \green{\tt: \implies a = 2 { \: m/s}^{2} } \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies f = ma \\ \\ \tt: \implies F= 10 \times 2 \\ \\ \green{\tt: \implies F= 20 \: N} \\ \\ \green{\tt \therefore Force \: require \: is \: 20 \: N}$