Question

(iv) p^2 q^2 + 10pqr + 25r^2 , than p=2 , q= -1, and r=3​

Answer 1

Answer:

169

Step-by-step explanation:

$p^2 q^2 + 10pqr + 25r^2$

when p = 2 , q = -1, and r = 3

$( {2}^{2} \times { - 1}^{2} ) + 10 \times 2 \times ( - 1) \times 3 + 25( {3}^{2} )$

$(4 \times 1) + ( - 60) + (25 \times 9)$

$4 - 60 + 225$

$229 - 60$

$169$