Question

(iv) Principal = Rs 12000, Rate of Interest = 18% per annum and Time = 4 months.
​

Answer 1

Step-by-step explanation:

Given Principal = Rs 12000,

Rate of Interest = 18% per annum and Time = 4 months = (4/12) = (1/3) years

We know that simple interest = (P × T × R)/100

On substituting these values in above equation we get

SI = (12000 × (1/3) × 18)/100

SI = (12000 × 1 × 18)/100 × 3

= Rs 720

Answer 2

$si = \frac{p \times r \times t}{100} \\ = \frac{12000 \times 18 \times 4}{100} \\ = 120 \times 18 \times 4 \\ = 8640$

Here

• P is Principal (in Rs.)
• R is rate
• T is time