Question

(iv) sin 30° + tan 45º - cosec 60° sec 30° + cos 60° + cot 45° 30 0​ naswer

Answer 1

Explanation:

$\large \bold{your \: question} :$

$\underline{sin 30° + tan 45º - cosec 60° sec 30° + cos 60° + cot 45°}$

$\large \bold \colorbox{blue}{your \: answer} :$

We know that,

$\sin(30) = \frac{1}{2}$

$\tan(45) = 1$

$\cosec( 60) = \frac{2}{ \sqrt{3} }$

$\sec(30) = \frac{2}{ \sqrt{3} }$

$\cos(60) = \frac{1}{2}$

$\cot(45) = 1$

• Therefore, placing all the values:

$= \large \bold{ \frac{1}{2} + 1 -( \frac{2}{ \sqrt{3} } )( \frac{2}{ \sqrt{3} } ) + \frac{1}{2} + 1}$

$= \large \bold{\frac{1}{2} + 1 + \frac{1}{2} + 1 - \frac{4}{3} }$

$= \large \bold{ \frac{1 \times 3 + 6 + 3 + 6 - 4 \times 2}{6} }$

$= \large \bold{ \frac{18 - 8}{6}}$

$= \large \bold{ \frac{10}{6} }$

$= \large \bold{\frac{ \cancel {10}}{ \cancel {6}} }$

$= \large \bold{\frac{5}{3} }$

$\colorbox{blue}{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$