Question

(iv) The amount of money in the account every year, when 7 10000 is deposited at
compound interest at 8 % per annum.
w forme frap when the first to​

Answer 1

Answer:

Amount deposited initially = P = rs. 10,000

Rate of interest = R = 8% p.a [at C.I.]

∴ A = P [ 1 + R/100 ] ⁿ

→ 10,000 [1+8 / 100]

= 10,000 × 108/100

= 10800

→ 10,000 [1+8 / 100]²

= 10,000 × 108/100 × 108/100

= 11664

→ 10,000[1+8/100]³

= 10,000 × 108×108×108

100×100×100

= 12597.12

the terms 10800, 11664, 12597.12....

a₂-a₁ = 800

a₃-a₂ = 864

a₄-a₃ = 933.12

Here, a=10,000

But, a₂-a₁ ≠ a₃-a₂ ≠ a₄-a₃

∴ the given situation doesn't represent an A.P

Answer 2

We know that if Rs. P is deposited at r% compound interest per annum for n years, the amount of money will be:

P(1+r/100)n

Therefore, after each year, the amount of money will be;

10000(1+8/100), 10000(1+8/100)2, 10000(1+8/100)3……

Clearly, the terms of this series do not have the common difference between them. Therefore, this is not an A.P.