Question

(iv) The brakes applied to a car produce an acceleration of 5 m/s2 in the opposite direction to the motion. If the car takes 4 s to stop after the application of brakes, calculate the distance it travels during this time. (a) 12 m (b) 15 m (c) 20 m (d) 40 m

Answer 1

Explanation:

Given:

Accerleration: a=−6 m/s2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+21at2

s=12×2+21×(−6)×4

⇒s=12 m