iv) The magnitude of vector product of two
unit vectors making an angle of 60' with
each other is
(A) 1
(B)2
(C)3/2 (D) 3/2
Answers
Answered by
5
Answer:
d is correct options
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Answered by
0
Answer:
a×b = /a/ /b/ sinx , hence magnitude of unit vectors is 1 so, a×b=1×1×sin60 =root3/2 mode value is 3/4
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