Question

iv) The magnitude of vector product of two
unit vectors making an angle of 60° with
each other is
(A) 1
(B) 2
(C) 3/2 (D) √3/2​

Answer 1

Given that,

Two unit vectors making an angle of 60°.

To find,

The magnitude of vector product of two  unit vectors.

Solution,

We have, $|A|=|B|=1$

We know that, vector product is given by :

$A\times B=|A||B|\sin\theta$

The magnitude of vector product

$|A\times B|=|A||B|\sin\theta\\\\=\sin60\\\\=\dfrac{\sqrt3}{2}$

Hence, the correct option is (D).

Answer 2

Hola ⚘⚘

Given:

• two unit vectors making an angle of 60°;

Tofind:

• The magnitude of vector product of two vectors

Calculation:

>> |A| = |B| = 1 (We have)

>> A * B = |A||B| sin θ

the magnitude of vector product

>> |A * B| = |A||B| sin θ

>> sin 60°

>> √3/2

hence, the magnitude of vector product of two unit vectors making an angle of 60° with each other is √3/2.

>> ∴ Option (d) is correct [✓]