(iv) The minute's hand of a clock is 7 cm. How length does the minute's hand move in 15
minutes?
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given: r = length of minute hand = 7 cm
angle Θ = 90° [ 15 minutes equals 90° ]
L = (2πrΘ)/360
L = (2πr x 90)/360
L = (2 x 3.14 x 7)/4
L = 10.99 ≈ 11 cm
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