Question

iv) The remainder when x' + ax? + 6x + a is divided by (x + a) is:​

Answer 1

Step-by-step explanation:

We have x

3

−ax

2

+6x−a

Apply remainder theorem

x−a=0

x=a

Put x=a in equation.

(a)

3

−a(a)

2

+6a−a

=a

3

−a

3

+6a−a

=6a−a

=5a

Answer 2

Answer:

$Given : 16x4+54x</p><p></p><p>We can write the given question as,</p><p></p><p>16x4+54x=2x(8x3+27)</p><p></p><p>According to the equation,</p><p>a3+b3=(a+b)(a2−ab+b2)</p><p></p><p>So we get,</p><p>2x(8x3+27)=2x((2x)3+33)</p><p></p><p>Using the equation,</p><p>=2x((2x)+3)((2x)2−(2x)(3)+(3)2)</p><p></p><p>16x4+54x=2x(2x+3)(4x2−6x+9) </p><p></p><p>$

hope it will help u