Question

iv ) The sum of three consecutive natural numbers is 33. What are the numbers?​

Answer 1

Answer:

This sum is represented by

(n)+(n+1)+(n+2)=33 ,

where n is the first number of the sequence.

Doing the sum in the left side of this expression, we'll have:

n+n+n+1+2=33 3n+3=33 3n=33−3 3n=30n=10

Testing, 10+11+12=33 .

Answer 2

Step-by-step explanation:

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