Question

iv) The taxi charges in a city consist of a fixed charge together with the charge for
distance covered. For a distance of 10 km, the charge paid is Rs 105 and f
journey of 15 km, the charge paid is Rs 155. What are the fixed charges and
chatge per km? How much does a person have to pay for travelling a distanc
25 km?
9
if 2 is added to both the numerator and the denomir
Afrin hermes​

Answer 1

Answer:

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Step-by-step explanation:

Let fixed charge be Rs x and charge per km be Rs y.

⇒x+10y=105...(1)

⇒x+15y=155..(2).

Now From eq 2

⇒15y=155−x

⇒y=

15

155−x

...(3)

Substituting y from eq3 in eq1

⇒x+

15

10(155−x)

=105

⇒15x+1550−10x=1575

⇒5x=1575−1550

⇒5x=25

⇒x=5

Substituting x in eq2

⇒5+15y=155

⇒15y=155−5

⇒15y=150

⇒y=10

Hence x=5 and y=10

Fixed charge is Rs.55 and the charge per kilometer is Rs.1010

For 2525 km person have to pay = 5+10×25=255Rs.