iv)The total surface area of the combined figure i.e. hemispherical dome with
radius 14m and cuboidal shaped top with dimensions 8m x 6m x 4m is-
a) 1200 sq.m
b) 1232 sq.m
c) 1393 sq.m
d) 1932 sq.m
Answers
Answer:
1392 sq.m
Step-by-step explanation:
perimeter of circle+csa of rectangle
perimeter of circle=1232(using the formula 2pie R square
now TSA of the figure=perimeter of circle+csa of rectamgle
1232+2h(l+b)+lh
1232+2*4(8+6)+8*6
1232+112+48
1232+160
1392sq.m
According the question, we have to find out the total surface area of the combined figure.
A hemispherical dome with radius 14m and cuboidal shaped top with dimensions 8m x 6m x 4m ( given).
We have to calculate total surface area of the combined figure .
which is (TSA of hemisphere + LSA of cuboid). ( TSA = Total surface area, LSA=Lateral surface area)
First we calculate TSA of hemisphere
Foumule of TSA of Hemisphere = 3πr² (π = 22/7 r = 14 = radius)
TSA of Hemisphere = 3(22/7) (14)²
= 1848 m²
In next step we will calculate LSA of Cuboid
Formula of LSA of Cuboid = 2(l + b) h ( l=8m, b=6m, h=4m)
LSA of Cuboid = 2(8 + 6) 4
LSA of Cuboid =112 m²
Here we will calculate the total surface area of the combined figure :-
( TSA + LSA) unite²
= (1848 + 112)m²
= 1960 m²
Hence the total surface area of the combined figure will be 1960 m².
Ans :- All given options are incorrect. The total surface area of the combined figure will be 1960 m².
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